Question
JL¯¯¯¯¯¯¯
is a perpendicular bisector of KM¯¯¯¯¯¯¯¯¯¯
. Hallie locates point H
along line segment JL¯¯¯¯¯¯¯
. If the length of KH¯¯¯¯¯¯¯¯¯
is given by 6y+3
and the length of HM¯¯¯¯¯¯¯¯¯¯
is given by 2y+7
, what is the length in units of segment HM¯¯¯¯¯¯¯¯¯¯
? (answer in two sentences and in normal numbers)
is a perpendicular bisector of KM¯¯¯¯¯¯¯¯¯¯
. Hallie locates point H
along line segment JL¯¯¯¯¯¯¯
. If the length of KH¯¯¯¯¯¯¯¯¯
is given by 6y+3
and the length of HM¯¯¯¯¯¯¯¯¯¯
is given by 2y+7
, what is the length in units of segment HM¯¯¯¯¯¯¯¯¯¯
? (answer in two sentences and in normal numbers)
Answers
GPT-4o mini
Since JL is the perpendicular bisector of KM, we know that KH and HM are equal in length. Setting the expressions equal gives us \(6y + 3 = 2y + 7\).
Solving for \(y\), we have \(4y = 4\), which simplifies to \(y = 1\). Substituting \(y\) back into the expression for HM, we find \(HM = 2(1) + 7 = 9\).
Thus, the length of segment HM is 9 units.
Solving for \(y\), we have \(4y = 4\), which simplifies to \(y = 1\). Substituting \(y\) back into the expression for HM, we find \(HM = 2(1) + 7 = 9\).
Thus, the length of segment HM is 9 units.