Since \( JL \) is the perpendicular bisector of \( KM \), it means that \( KH \) is equal to \( HM \). Therefore, we can set the two expressions for the lengths equal to each other:
\[ KH = HM \]
Given that \( KH = 6y + 3 \) and \( HM = 2y + 7 \), we set up the equation:
\[ 6y + 3 = 2y + 7 \]
Now, we'll solve for \( y \):
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Subtract \( 2y \) from both sides: \[ 4y + 3 = 7 \]
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Subtract 3 from both sides: \[ 4y = 4 \]
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Divide both sides by 4: \[ y = 1 \]
Now that we have the value of \( y \), we can find the length of segment \( HM \):
Substituting \( y = 1 \) into the expression for \( HM \):
\[ HM = 2y + 7 = 2(1) + 7 = 2 + 7 = 9 \]
Thus, the length of segment \( HM \) is \( \boxed{9} \).