Asked by Anonymous
a rectangle has an area of ( x3+x2-10x+8) square meters, and a width of (x+4) meters. Find its length.
Answers
Answered by
Reiny
You probably meant to say
x^3+x^2-10x+8
since area = l x w
x^3+x^2-10x+8 = length(x+4)
length = (x^3+x^2-10x+8)/(x+4)
= x^2 - 3x + 2
(I used synthetic division, you could also use long algebraic division)
x^3+x^2-10x+8
since area = l x w
x^3+x^2-10x+8 = length(x+4)
length = (x^3+x^2-10x+8)/(x+4)
= x^2 - 3x + 2
(I used synthetic division, you could also use long algebraic division)
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