Asked by Anonymous
The area of a rectangle is 72 square inches and the perimeter is 44 inches. Find its dimensions.
Answers
Answered by
bobpursley
area=lw
lw=72 or l=72/w
P=2(l+w)=2(72/w + w)
44=2(72/w+w)
22w=7+w^2
w^2-22w+72=0
(w-18)(w-4)=0
so w is 18, or 4, and you can solve for the length from l=72/w
lw=72 or l=72/w
P=2(l+w)=2(72/w + w)
44=2(72/w+w)
22w=7+w^2
w^2-22w+72=0
(w-18)(w-4)=0
so w is 18, or 4, and you can solve for the length from l=72/w
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