Question

We are pretending that tongue-curling in humans is a dominant genetic trait.

Suppose a man who is Tt for tongue-curling marries a woman who is also Tt for this trait. What are the possible genotypes and phenotypes of their children, and the percent chance for each?


Genotype
TT
Tt
tt

Fill in the blanks
Phenotype (curl or no curl)
Blank
Blank
Blank

Percent Chance (number only)
Blank
Blank
Blank

Word Bank:
50
0
75
curl
25
curl
no curl
25
100

Answer 1

To determine the genotypes and phenotypes of the children from a Tt (tongue-curling) man and a Tt (tongue-curling) woman, we can set up a Punnett square.

The possible gametes from each parent (T = tongue-curling, t = no tongue-curling) are:

- Parent 1 (Tt): T, t
- Parent 2 (Tt): T, t

The Punnett square would look like this:

| | T | t |
|-------|-----|-----|
| **T** | TT | Tt |
| **t** | Tt | tt |

From this, the possible genotypes for their children are:

1. TT (homozygous dominant)
2. Tt (heterozygous)
3. tt (homozygous recessive)

Now, we can find the corresponding phenotypes and the percent chances for each genotype:

1. Genotype: TT
- Phenotype: curl
- Percent Chance: 25 (1 out of 4)

2. Genotype: Tt
- Phenotype: curl
- Percent Chance: 50 (2 out of 4)

3. Genotype: tt
- Phenotype: no curl
- Percent Chance: 25 (1 out of 4)

Now we can fill in the table:

**Genotype**
- TT
- Tt
- tt

**Phenotype (curl or no curl)**
- curl
- curl
- no curl

**Percent Chance (number only)**
- 25
- 50
- 25

So the final answers in the structure provided would be:

- Curl (for TT)
- Curl (for Tt)
- No curl (for tt)

- 25
- 50
- 25

The corresponding filled table is:

**Genotype**
- TT
- Tt
- tt

**Phenotype (curl or no curl)**
- curl
- curl
- no curl

**Percent Chance (number only)**
- 25
- 50
- 25