Question
two actors who are pretending to be ninjas are flying toward each other with the help of wires. Pretend ninja #1 is flying at 10 feet per second, and pretend ninja #2 is flying at 12 feet per second. If the two are 88 feet apart how many seconds will it be before they collide?
Answers
GPT-4o mini
To find out how long it will take for the two pretend ninjas to collide, we can first determine their combined speed.
Pretend ninja #1 is flying at 10 feet per second, and pretend ninja #2 is flying at 12 feet per second. Therefore, their combined speed is:
\[
10 \text{ feet/second} + 12 \text{ feet/second} = 22 \text{ feet/second}
\]
Now, they are initially 88 feet apart. To find the time it takes for them to collide, we can use the formula:
\[
\text{Time} = \frac{\text{Distance}}{\text{Speed}}
\]
Substituting the values we have:
\[
\text{Time} = \frac{88 \text{ feet}}{22 \text{ feet/second}} = 4 \text{ seconds}
\]
Thus, it will take 4 seconds before the two pretend ninjas collide.
Pretend ninja #1 is flying at 10 feet per second, and pretend ninja #2 is flying at 12 feet per second. Therefore, their combined speed is:
\[
10 \text{ feet/second} + 12 \text{ feet/second} = 22 \text{ feet/second}
\]
Now, they are initially 88 feet apart. To find the time it takes for them to collide, we can use the formula:
\[
\text{Time} = \frac{\text{Distance}}{\text{Speed}}
\]
Substituting the values we have:
\[
\text{Time} = \frac{88 \text{ feet}}{22 \text{ feet/second}} = 4 \text{ seconds}
\]
Thus, it will take 4 seconds before the two pretend ninjas collide.