Question
How do you find the roots to x^2-6x+3
Answers
bobpursley
I assume it is equal to zero, you can't find roots unless you have an equation.
x^2-6x+3=0
x= (-b+-sqrt(b^2-4ac) /2a
x= (6+-sqrt(36-12) )/2=3+-sqrt(24)
x^2-6x+3=0
x= (-b+-sqrt(b^2-4ac) /2a
x= (6+-sqrt(36-12) )/2=3+-sqrt(24)