Asked by Neel
Find the roots for the given equstion
p^4+m^4=0
p^4+m^4=0
Answers
Answered by
Steve
p^4+m^4
= (p^2+m^2 i)(p^2 - m^2 i)
= (p-m√i*i)(p+m√i*i)(p+m√i)(p-m√i)
= (p-m√i^3)(p+m√i^3)(p+m√i)(p-m√i)
= (p-m√-i)(p+m√-i)(p+m√i)(p-m√i)
I assume you can figure out what √i and √-i are. (de Moivre's law)
= (p^2+m^2 i)(p^2 - m^2 i)
= (p-m√i*i)(p+m√i*i)(p+m√i)(p-m√i)
= (p-m√i^3)(p+m√i^3)(p+m√i)(p-m√i)
= (p-m√-i)(p+m√-i)(p+m√i)(p-m√i)
I assume you can figure out what √i and √-i are. (de Moivre's law)
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