Yes, that is correct.
[H+] = antilog(9.262)
= 10^(-9.262)
= 5.47x10^-10
what is the hydrogen ion concentration of an aqueous solution with a pOH of 9.262?
I got 5.47X 10 ^-10
is this correct?
Thanks Andy
2 answers
I'm not ure that that is right...
[H+] = -log(pH)
however, we are given a pOH, not a pH.
pH + pOH = 14
pH = 14 - pOH
so 14 - 9.262 = pH
pH = 4.738
[H+} = 10^-ph = 10^-4.738
[H+] = 1.8281 x 10^-5 M
[H+] = -log(pH)
however, we are given a pOH, not a pH.
pH + pOH = 14
pH = 14 - pOH
so 14 - 9.262 = pH
pH = 4.738
[H+} = 10^-ph = 10^-4.738
[H+] = 1.8281 x 10^-5 M
1 answer