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Solve x−1/3≤1/2 . (1 point) Responses x≤56 x less-than-or-equal-to Start Fraction 5 over 6 End Fraction x≤16 x less-than-or-equ...Asked by tomdaya
Solve x−1/3≤1/2
. (1 point)
Responses
x≤16
x less-than-or-equal-to Start Fraction 1 over 6 End Fraction
x≥56
x greater-than-or-equal-to Start Fraction 5 over 6 End Fraction
x≤56
x less-than-or-equal-to Start Fraction 5 over 6 End Fraction
x≥16
. (1 point)
Responses
x≤16
x less-than-or-equal-to Start Fraction 1 over 6 End Fraction
x≥56
x greater-than-or-equal-to Start Fraction 5 over 6 End Fraction
x≤56
x less-than-or-equal-to Start Fraction 5 over 6 End Fraction
x≥16
Answers
Answered by
GPT-4o mini
To solve the inequality \( x - \frac{1}{3} \leq \frac{1}{2} \), follow these steps:
1. Add \( \frac{1}{3} \) to both sides of the inequality:
\[
x \leq \frac{1}{2} + \frac{1}{3}
\]
2. Find a common denominator to add the fractions. The least common denominator of 2 and 3 is 6.
\[
\frac{1}{2} = \frac{3}{6}
\]
\[
\frac{1}{3} = \frac{2}{6}
\]
3. Now add the two fractions:
\[
\frac{3}{6} + \frac{2}{6} = \frac{5}{6}
\]
4. Thus, the inequality becomes:
\[
x \leq \frac{5}{6}
\]
So the solution is:
\[
x \leq \frac{5}{6}
\]
The correct response is:
**x ≤ 5/6**.
1. Add \( \frac{1}{3} \) to both sides of the inequality:
\[
x \leq \frac{1}{2} + \frac{1}{3}
\]
2. Find a common denominator to add the fractions. The least common denominator of 2 and 3 is 6.
\[
\frac{1}{2} = \frac{3}{6}
\]
\[
\frac{1}{3} = \frac{2}{6}
\]
3. Now add the two fractions:
\[
\frac{3}{6} + \frac{2}{6} = \frac{5}{6}
\]
4. Thus, the inequality becomes:
\[
x \leq \frac{5}{6}
\]
So the solution is:
\[
x \leq \frac{5}{6}
\]
The correct response is:
**x ≤ 5/6**.
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