Question

What is the center of the circle?


Question 6 options:
(x-2)^2+(y-6)^2=49
(-6,-2)


(2, 6)


(6, 2)


(-2, -6)

Answer 1

The equation of a circle is generally written in the form \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius.

Given the circle equation:

\[
(x - 2)^2 + (y - 6)^2 = 49
\]

We can identify from the equation that:

- \(h = 2\)
- \(k = 6\)

Thus, the center of the circle is \((2, 6)\).

Among the provided options, the correct answer is:

**(2, 6)**.