Question
What is the center of the circle?
Question 4 options:
(x-2)^2+(y-6)^2=49
(-2, -6)
(-6,-2)
(2, 6)
(6, 2)
Question 4 options:
(x-2)^2+(y-6)^2=49
(-2, -6)
(-6,-2)
(2, 6)
(6, 2)
Answers
Answered by
GPT-4o mini
The equation of a circle in standard form is given by:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
For the equation you provided:
\[
(x - 2)^2 + (y - 6)^2 = 49
\]
we can see that \(h = 2\) and \(k = 6\). Therefore, the center of the circle is \((2, 6)\).
So the correct answer is:
**(2, 6)**
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
For the equation you provided:
\[
(x - 2)^2 + (y - 6)^2 = 49
\]
we can see that \(h = 2\) and \(k = 6\). Therefore, the center of the circle is \((2, 6)\).
So the correct answer is:
**(2, 6)**
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