Question

Graph the inequality on the axes below.
3, x, plus, 2, y, is less than or equal to, minus, 12
3x+2y≤−12


just the 2 points pls

Answer 1

To graph the inequality \(3x + 2y \leq -12\), we first need to convert it into an equation to find the boundary line. The equation is:

\[ 3x + 2y = -12 \]

Next, we can find the intercepts to plot the points:

1. **x-intercept**: Set \(y = 0\):
\[
3x + 2(0) = -12 \implies 3x = -12 \implies x = -4
\]
So the x-intercept is \((-4, 0)\).

2. **y-intercept**: Set \(x = 0\):
\[
3(0) + 2y = -12 \implies 2y = -12 \implies y = -6
\]
So the y-intercept is \((0, -6)\).

Now we have the two points to plot the boundary line:
1. \((-4, 0)\)
2. \((0, -6)\)

These are the two points you can use to graph the line for the inequality \(3x + 2y \leq -12\). To indicate the area satisfying the inequality, shade below the line when you finish graphing it.