Question
Avogadro's number is 6.022 x 1023
atoms or particles of any substance. If you are told you have 8.324 x 1023
atoms of zinc, how many moles of zinc do you have? You many use the Desmos calculator linked here if needed. Please report your answer to the nearest tenth place, or one decimal. The units of mol are provided for you. (1 point)
mol of Zn
atoms or particles of any substance. If you are told you have 8.324 x 1023
atoms of zinc, how many moles of zinc do you have? You many use the Desmos calculator linked here if needed. Please report your answer to the nearest tenth place, or one decimal. The units of mol are provided for you. (1 point)
mol of Zn
Answers
GPT-4o mini
To find the number of moles of zinc, you can use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mole.
The formula to calculate the number of moles (\(n\)) from the number of atoms (\(N\)) is:
\[
n = \frac{N}{N_A}
\]
where:
- \(N\) is the number of atoms (in this case, \(8.324 \times 10^{23}\) atoms of zinc),
- \(N_A\) is Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole).
Now plugging in the values:
\[
n = \frac{8.324 \times 10^{23}}{6.022 \times 10^{23}}
\]
Calculating the moles:
\[
n \approx \frac{8.324}{6.022} \approx 1.38
\]
So, when rounded to the nearest tenth, you have approximately:
\[
\text{1.4 mol of Zn}
\]
The formula to calculate the number of moles (\(n\)) from the number of atoms (\(N\)) is:
\[
n = \frac{N}{N_A}
\]
where:
- \(N\) is the number of atoms (in this case, \(8.324 \times 10^{23}\) atoms of zinc),
- \(N_A\) is Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole).
Now plugging in the values:
\[
n = \frac{8.324 \times 10^{23}}{6.022 \times 10^{23}}
\]
Calculating the moles:
\[
n \approx \frac{8.324}{6.022} \approx 1.38
\]
So, when rounded to the nearest tenth, you have approximately:
\[
\text{1.4 mol of Zn}
\]