Question
Avogadro's number is 6.022 x 1023
atoms or particles of any substance. If you are told you have 2.1077 x 1024
atoms of zinc, how many moles of zinc do you have? Please report your answer to the nearest tenth place, or one decimal. The units of mol are provided for you. (1 point)
mol of Zn
atoms or particles of any substance. If you are told you have 2.1077 x 1024
atoms of zinc, how many moles of zinc do you have? Please report your answer to the nearest tenth place, or one decimal. The units of mol are provided for you. (1 point)
mol of Zn
Answers
GPT-4o mini
To find the number of moles of zinc (Zn), you can use the equation:
\[
\text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}}
\]
Given:
- Number of zinc atoms = \( 2.1077 \times 10^{24} \) atoms
- Avogadro's number = \( 6.022 \times 10^{23} \) atoms/mol
Now, substitute the values into the equation:
\[
\text{moles of Zn} = \frac{2.1077 \times 10^{24}}{6.022 \times 10^{23}}
\]
Calculating this gives:
\[
\text{moles of Zn} \approx \frac{2.1077}{6.022} \times 10^{24 - 23} \approx \frac{2.1077}{6.022} \approx 0.350
\]
Thus,
\[
\text{moles of Zn} \approx 3.5 \text{ mol}
\]
So, the number of moles of zinc you have is approximately **3.5 mol of Zn**.
\[
\text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}}
\]
Given:
- Number of zinc atoms = \( 2.1077 \times 10^{24} \) atoms
- Avogadro's number = \( 6.022 \times 10^{23} \) atoms/mol
Now, substitute the values into the equation:
\[
\text{moles of Zn} = \frac{2.1077 \times 10^{24}}{6.022 \times 10^{23}}
\]
Calculating this gives:
\[
\text{moles of Zn} \approx \frac{2.1077}{6.022} \times 10^{24 - 23} \approx \frac{2.1077}{6.022} \approx 0.350
\]
Thus,
\[
\text{moles of Zn} \approx 3.5 \text{ mol}
\]
So, the number of moles of zinc you have is approximately **3.5 mol of Zn**.