Question

Keep going. Let's try to get
4
1
​
s alone on the right side. How could you get rid of the 10 on the right side so that
4
1
​
s is alone on the right, while keeping the equation balanced?
4
3
​
s + 8
=
s + 10
−
4
3
​
s
−
4
3
​
s

8
=
4
1
​
s + 10

Add 10 to both sides

Divide both sides by 10

Subtract 10 from both sides

Answer 1

To isolate \( \frac{41}{4}s \) on the right side of the equation \( 8 = \frac{41}{4}s + 10 \), you should follow these steps to eliminate the 10 on the right side while maintaining the balance of the equation:

1. **Subtract 10 from both sides**:

\[
8 - 10 = \frac{41}{4}s + 10 - 10
\]

This simplifies to:

\[
-2 = \frac{41}{4}s
\]

Now, you have \( \frac{41}{4}s \) alone on the right side. If your goal is to solve for \( s \), you can divide both sides by \( \frac{41}{4} \).

2. **Multiply both sides by the reciprocal of \( \frac{41}{4} \)** (which is \( \frac{4}{41} \)):

\[
s = -2 \cdot \frac{4}{41}
\]

This gives:

\[
s = -\frac{8}{41}
\]

So \( s \) is isolated and equals \( -\frac{8}{41} \).