Subtract 10 from each side of the equation to get rid of 10 on the right, so that 3r is alone on the right side of the equation.

4
1

(12r−8)
=
6r+10

3r − 2
=
6r + 10

3r

3r

−2
=
3r +10

10

10

=

1 answer

Let's solve the equation step by step:

Given: \[ 3r - 2 = 6r + 10 \]

Step 1: Subtract \(10\) from both sides to isolate the terms involving \(r\):

\[ 3r - 2 - 10 = 6r + 10 - 10 \]

This simplifies to:

\[ 3r - 12 = 6r \]

Step 2: Next, subtract \(3r\) from both sides to get all the \(r\) terms on one side:

\[ 3r - 3r - 12 = 6r - 3r \]

This simplifies to:

\[ -12 = 3r \]

Step 3: Finally, divide both sides by \(3\) to solve for \(r\):

\[ \frac{-12}{3} = r \]

This gives us:

\[ r = -4 \]

So, the solution to the original equation is: \[ r = -4 \]