Question

Subtract 10 from each side of the equation to get rid of 10 on the right, so that 3r is alone on the right side of the equation.
4
1
​
(12r−8)
=
6r+10

3r − 2
=
6r + 10
−
3r
−
3r

−2
=
3r +10
−
10
−
10

=

Answer 1

Let's solve the equation step by step:

Given:
\[
3r - 2 = 6r + 10
\]

**Step 1:** Subtract \(10\) from both sides to isolate the terms involving \(r\):

\[
3r - 2 - 10 = 6r + 10 - 10
\]

This simplifies to:

\[
3r - 12 = 6r
\]

**Step 2:** Next, subtract \(3r\) from both sides to get all the \(r\) terms on one side:

\[
3r - 3r - 12 = 6r - 3r
\]

This simplifies to:

\[
-12 = 3r
\]

**Step 3:** Finally, divide both sides by \(3\) to solve for \(r\):

\[
\frac{-12}{3} = r
\]

This gives us:

\[
r = -4
\]

So, the solution to the original equation is:
\[
r = -4
\]