There are many ways you could solve this equation. We need to get s alone on one side, and a constant number alone on the other side. Since s is inside the parentheses on the left, we can use the distributive property to rewrite the equation without parentheses. Go for it. Distribute the

Question

5
1
​
to 5s−15. You can think of this as (5s−15) is being multiplied by
5
1
​
.
5
1
​
(5s − 15) = 9s + 9 ______
= 9s + 9

Answer 1

To distribute \( \frac{5}{1} \) (which is the same as 5) to the expression \( (5s - 15) \), you can apply the distributive property as follows:

\[ 5 \cdot (5s - 15) = 5 \cdot 5s - 5 \cdot 15 \]

This gives:

\[ 25s - 75 \]

Now, substituting this back into the equation, we have:

\[ 25s - 75 = 9s + 9 \]

Next, to isolate \( s \), we will move all the terms involving \( s \) to one side and the constant terms to the other side. Let's subtract \( 9s \) from both sides:

\[ 25s - 9s - 75 = 9 \]

This simplifies to:

\[ 16s - 75 = 9 \]

Now, add \( 75 \) to both sides to isolate the term with \( s \):

\[ 16s = 9 + 75 \]

This further simplifies to:

\[ 16s = 84 \]

Finally, divide both sides by \( 16 \) to solve for \( s \):

\[ s = \frac{84}{16} \]

To simplify \( \frac{84}{16} \):

The greatest common divisor of 84 and 16 is 4, so we can simplify:

\[ s = \frac{84 \div 4}{16 \div 4} = \frac{21}{4} \]

Thus, the solution for \( s \) is:

\[ s = \frac{21}{4} \] or \( 5.25 \) in decimal form.