Question

Add 6 to both sides to get rid of −6, so that 5h is alone on the left side of the equation.
2h − 6
=
−3h − 5
+
3h
+
3h

5h − 6
=
−5
+
6
+
6

=

Answer 1

Let's go through the steps to solve the equation you provided.

Starting with the original equation:

\[ 2h - 6 = -3h - 5 \]

You want to add 6 to both sides to eliminate the -6 on the left:

\[ 2h - 6 + 6 = -3h - 5 + 6 \]

This simplifies to:

\[ 2h = -3h + 1 \]

Next, add \(3h\) to both sides to get all terms involving \(h\) on the left:

\[ 2h + 3h = -3h + 3h + 1 \]

This simplifies to:

\[ 5h = 1 \]

If you were to add \(6\) to both sides (as part of another operation), it would look like:

From the equation \(5h = 1\):

If you want to add \(6\) to both sides:

\[ 5h + 6 = 1 + 6 \]

This simplifies to:

\[ 5h + 6 = 7 \]

So, you have correctly performed operations to isolate \(5h\) on one side, but now we see it could represent separate steps, confirming \(5h = 1\) and then adding \(6\).

If you are looking for the final line from the first steps, that should result in:
\[ 5h = 1 \rightarrow 5h + 6 = 7 \]
but if you simply want the previous without adding:

Final statement of the isolated variable is:
\[ 5h = 1 \]

Let me know if you need further steps!