Question

The chef of a pizza place used 7 1/3 packages of pepperoni and 5/6 of a package of sausage. How much more pepperoni than sausage did the chef use?

Write your answer as a fraction or as a whole or mixed number.

packages

Answer 1

To find out how much more pepperoni than sausage the chef used, we need to subtract the amount of sausage from the amount of pepperoni.

First, convert the mixed number \(7 \frac{1}{3}\) into an improper fraction:

\[
7 \frac{1}{3} = 7 + \frac{1}{3} = \frac{21}{3} + \frac{1}{3} = \frac{21 + 1}{3} = \frac{22}{3}
\]

Now we have:

- Amount of pepperoni: \(\frac{22}{3}\)
- Amount of sausage: \(\frac{5}{6}\)

Next, we need to perform the subtraction:

\[
\frac{22}{3} - \frac{5}{6}
\]

To subtract these fractions, we need a common denominator. The least common multiple of 3 and 6 is 6. We convert the first fraction:

\[
\frac{22}{3} = \frac{22 \times 2}{3 \times 2} = \frac{44}{6}
\]

Now we can subtract:

\[
\frac{44}{6} - \frac{5}{6} = \frac{44 - 5}{6} = \frac{39}{6}
\]

Next, we can simplify \(\frac{39}{6}\):

\[
\frac{39 \div 3}{6 \div 3} = \frac{13}{2}
\]

Finally, convert \(\frac{13}{2}\) into a mixed number:

\[
\frac{13}{2} = 6 \frac{1}{2}
\]

Thus, the amount of pepperoni used was \(6 \frac{1}{2}\) packages more than the sausage.

The final answer is:

\[
\boxed{6 \frac{1}{2}}
\] packages.