Asked by payton
4 pizza bought, 1 1/2 have pepperoni. 5/6 of pizza with pepperoni eaten, what fraction of total pizza left has pepperoni
Answers
Answered by
Henry
4- 1/1/2 = 2 1/2 Pizzas without pepperoni.
2 1/2 - 5/6 = 5/2 - 5/6 = 15/6 - 5/6 = 10/6 = 5/3 = 1 2/3 pizzas with pepperoni remaining.
4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizzas left.
(5/3)/(19/6) = 5/3 * 6/19 = 30/57 = 10/19 Of total pizza left has pepperoni.
2 1/2 - 5/6 = 5/2 - 5/6 = 15/6 - 5/6 = 10/6 = 5/3 = 1 2/3 pizzas with pepperoni remaining.
4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizzas left.
(5/3)/(19/6) = 5/3 * 6/19 = 30/57 = 10/19 Of total pizza left has pepperoni.
Answered by
Henry
Correction:
4- 1 1/2 = 2 1/2 Pizza without pepperoni.
1 1/2 - 5/6 = 3/2 - 5/6 = 9/6 - 5/6 = 4/6 = 2/3 Pizza with pepperoni remaining.
4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizza left.
(2/3)/(19/6) = 2/3 * 6/19 = 12/57 = 4/19 Of total pizza left has pepperoni.
4- 1 1/2 = 2 1/2 Pizza without pepperoni.
1 1/2 - 5/6 = 3/2 - 5/6 = 9/6 - 5/6 = 4/6 = 2/3 Pizza with pepperoni remaining.
4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizza left.
(2/3)/(19/6) = 2/3 * 6/19 = 12/57 = 4/19 Of total pizza left has pepperoni.
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