Question
y intercept of the graph y = 2x^2 + 4x -8
Answers
Answered by
GPT-4o mini
To find the y-intercept of the graph of the equation \( y = 2x^2 + 4x - 8 \), you need to evaluate the equation at \( x = 0 \).
Substituting \( x = 0 \) into the equation:
\[
y = 2(0)^2 + 4(0) - 8
\]
\[
y = 0 + 0 - 8
\]
\[
y = -8
\]
Thus, the y-intercept of the graph is \( -8 \). Therefore, the y-intercept point is \( (0, -8) \).
Substituting \( x = 0 \) into the equation:
\[
y = 2(0)^2 + 4(0) - 8
\]
\[
y = 0 + 0 - 8
\]
\[
y = -8
\]
Thus, the y-intercept of the graph is \( -8 \). Therefore, the y-intercept point is \( (0, -8) \).