Asked by Ev

How many joules of heat are lost by 3399kg granite as it cools from 41.7 degrees Celcius to -13.3 degrees Celcius? answer must be in joules not kJ

15 years ago

Answered by DrBob222

q = mass granite x specific heat granit x delta T.

15 years ago

Answered by Anonymous

ok so,

q=3399kg x 0.803 x 55
q = 150.116

Is that correct?

15 years ago

Answered by Ev

so then my answer would be 150.116kJ which equals 150116835J. Is that correct???

15 years ago

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