No. NaNO3 is soluble. Cu(OH)2 is not soluble. Here is a list of solubility rules.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
1) Write a balanced chemical equation for the reaction between Cu(NO3)2 * 3 H2O and NaOH. Underline the formula for the precipitate produced by this reaction. (The water of hydration in Cu(NO3)2 * 3 H2O appears as liquid water on the right side of the equation)
1. Cu(NO3)2.3H2O(aq) + NaOH(aq) --> Cu(OH)2(s) + H2O + NaNO3(aq)
We can't underline but (s) means a solid ppt. You will need to balance it.
Why is Cu(OH)2 the precipitate in this solution? Shouldn't it be NaNO3?
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