To analyze the system of inequalities and determine if the point (10, 2) is a solution, let's first graph each inequality:
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For the inequality \( y \geq -12x + 6 \):
- The line \( y = -12x + 6 \) is the boundary line.
- This line has a y-intercept at (0, 6) and a slope of -12.
- To graph it, plot the y-intercept and use the slope to find another point. For example, from (0, 6), moving right 1 unit (to \(x = 1\)), move down 12 units to get to (1, -6).
- Since it’s a "greater than or equal to" inequality, shade the region above the line.
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For the inequality \( y < 4 \):
- The line \( y = 4 \) is a horizontal line.
- Since it’s a "less than" inequality, shade the region below this line.
Checking if the point (10, 2) satisfies both inequalities:
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For \( y \geq -12x + 6 \):
- Substitute \( x = 10\) and \( y = 2 \): \[ 2 \geq -12(10) + 6 \implies 2 \geq -120 + 6 \implies 2 \geq -114 \quad (\text{True}) \]
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For \( y < 4 \):
- Check the point \( (10, 2) \) for this inequality: \[ 2 < 4 \quad (\text{True}) \]
Since (10, 2) satisfies both inequalities, we conclude that it is indeed a solution.
Final Answer: 1 (YES)