Asked by liquidlew
A triangle has vertices (-3, 2), (0, 5), and (4, 2). What are the vertices after translating the triangle 3 units up? Draw a graph if necessary.(1 point)Responses (0, 2), (3, 5), and (7, 2) (0, 2), (3, 5), and (7, 2) (-3, 5), (0, 8), and (4, 5) (-3, 5), (0, 8), and (4, 5) (-3, -1), (0, 2), and (4, -1) (-3, -1), (0, 2), and (4, -1) (-6, 2), (-3, 5), and (1, 2)
Answers
Answered by
GPT-4o mini
To translate a triangle 3 units up, you need to add 3 to the y-coordinate of each vertex.
The original vertices of the triangle are:
1. Vertex A: (-3, 2)
2. Vertex B: (0, 5)
3. Vertex C: (4, 2)
Now, we will translate each vertex:
- For Vertex A:
\((-3, 2) \rightarrow (-3, 2 + 3) = (-3, 5)\)
- For Vertex B:
\((0, 5) \rightarrow (0, 5 + 3) = (0, 8)\)
- For Vertex C:
\((4, 2) \rightarrow (4, 2 + 3) = (4, 5)\)
After the translation, the new vertices are:
- A' (-3, 5)
- B' (0, 8)
- C' (4, 5)
Therefore, the vertices after translating the triangle 3 units up are:
**(-3, 5), (0, 8), and (4, 5)**.
The correct option is:
- (-3, 5), (0, 8), and (4, 5)
The original vertices of the triangle are:
1. Vertex A: (-3, 2)
2. Vertex B: (0, 5)
3. Vertex C: (4, 2)
Now, we will translate each vertex:
- For Vertex A:
\((-3, 2) \rightarrow (-3, 2 + 3) = (-3, 5)\)
- For Vertex B:
\((0, 5) \rightarrow (0, 5 + 3) = (0, 8)\)
- For Vertex C:
\((4, 2) \rightarrow (4, 2 + 3) = (4, 5)\)
After the translation, the new vertices are:
- A' (-3, 5)
- B' (0, 8)
- C' (4, 5)
Therefore, the vertices after translating the triangle 3 units up are:
**(-3, 5), (0, 8), and (4, 5)**.
The correct option is:
- (-3, 5), (0, 8), and (4, 5)