Question
An object with a height of 42 cm is placed 1.6 m in front of a concave mirror with a focal length of 0.45 m. Find the location and magnification of the image produced by the mirror, using the mirror and magnification equations.
Answers
drwls
First, you need to learn the equations. It's not that hard.
1/Do + 1/Di = 1/f
Do is the object distance from the mirror and Di is the distance to the image from the mirror. f is the focal length.
Use that equation to solve for Di.
1/1.6 + 1/Di = 1/0.45
1/Di = 1.597
Di = 0.6261 m
The magnification is M = Di/Do.
1/Do + 1/Di = 1/f
Do is the object distance from the mirror and Di is the distance to the image from the mirror. f is the focal length.
Use that equation to solve for Di.
1/1.6 + 1/Di = 1/0.45
1/Di = 1.597
Di = 0.6261 m
The magnification is M = Di/Do.