Asked by alex
The height of an object after it is released can be modeled by the function f(t)=-16t^2+vt+s, where t is the n?
The height of an object after it is released can be modeled by the function f(t)=-16t^2+vt+s, where t is the number of seconds after the object is released, v is the upward speed at release, and s is the starting height. If a quarterback throws a ball from his hand 6 feet in the air at a speed of 25 feet per second, how much time does his teammate have to catch the ball?
about 1.45 seconds
about 1.77 seconds
about 6 seconds
about 25 seconds
The height of an object after it is released can be modeled by the function f(t)=-16t^2+vt+s, where t is the number of seconds after the object is released, v is the upward speed at release, and s is the starting height. If a quarterback throws a ball from his hand 6 feet in the air at a speed of 25 feet per second, how much time does his teammate have to catch the ball?
about 1.45 seconds
about 1.77 seconds
about 6 seconds
about 25 seconds
Answers
Answered by
Steve
find how long it takes for the ball to drop 6 feet, starting with no upward velocity:
-16t^2 + 6 = 0
Looks like 0.6 to me
As that's not a choice, I expect there was some initial upward speed.
-16t^2 + 6 = 0
Looks like 0.6 to me
As that's not a choice, I expect there was some initial upward speed.
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