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Find, to the nearest degree, the solution set of 3sin^2x = 5 cosx+1 over the demain {x|0 degrees < or = to x which is < 360 degrees}
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Find the derivative of y with respect to x:
y=3sin^4(2-x)^-1 y=[3sin(2-x)^-1]^4 y'=4[3sin(2-x)^-1]^3 (-3cos(2-x)^-1)(-1)
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Can you help me with this? I did this many times and got different answers each time.
Find f. f ''(x) = 3e^x + 3sin(x) f(0) = 0
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integral from cosx to sinx (ln(8+3v)dv) y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2 Is
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