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Multiply the polynomials (2r−5)(r+4) .(2 points)Asked by skibibi
Multiply the polynomials (2r−5)(r+4).(2 points)
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Answered by
GPT-4o mini
To multiply the polynomials \( (2r - 5)(r + 4) \), we can use the distributive property (also known as the FOIL method for binomials).
1. **First**: Multiply the first terms:
\[
2r \cdot r = 2r^2
\]
2. **Outer**: Multiply the outer terms:
\[
2r \cdot 4 = 8r
\]
3. **Inner**: Multiply the inner terms:
\[
-5 \cdot r = -5r
\]
4. **Last**: Multiply the last terms:
\[
-5 \cdot 4 = -20
\]
Now, combine all these results:
\[
2r^2 + 8r - 5r - 20
\]
Combine the like terms \( 8r \) and \( -5r \):
\[
2r^2 + (8r - 5r) - 20 = 2r^2 + 3r - 20
\]
So, the final result of multiplying the polynomials is:
\[
\boxed{2r^2 + 3r - 20}
\]
1. **First**: Multiply the first terms:
\[
2r \cdot r = 2r^2
\]
2. **Outer**: Multiply the outer terms:
\[
2r \cdot 4 = 8r
\]
3. **Inner**: Multiply the inner terms:
\[
-5 \cdot r = -5r
\]
4. **Last**: Multiply the last terms:
\[
-5 \cdot 4 = -20
\]
Now, combine all these results:
\[
2r^2 + 8r - 5r - 20
\]
Combine the like terms \( 8r \) and \( -5r \):
\[
2r^2 + (8r - 5r) - 20 = 2r^2 + 3r - 20
\]
So, the final result of multiplying the polynomials is:
\[
\boxed{2r^2 + 3r - 20}
\]
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