To find the value of \( \log 88 \), we can use the change of base formula and the given values of \( \log 8 \) and \( \log 11 \).
Using the properties of logarithms, we can express \( 88 \) as \( 8 \times 11 \): \[ \log 88 = \log (8 \times 11) = \log 8 + \log 11 \]
Given:
- \( \log 8 \approx 0.9031 \)
- \( \log 11 \approx 1.0414 \)
Now substituting the values: \[ \log 88 \approx 0.9031 + 1.0414 \]
Calculating this sum: \[ \log 88 \approx 0.9031 + 1.0414 \approx 1.9445 \]
Thus, the value of \( \log 88 \) is approximately: \[ \log 88 \approx 1.9445 \]
So the correct response is: \[ \log 88 \approx 1.9445 \]