To calculate \(\log_{10} 88\) using the values provided for \(\log 8\) and \(\log 11\), we can use the property of logarithms that states:
\[ \log_{10} (a \cdot b) = \log_{10} a + \log_{10} b \]
First, we factor 88 into its prime factors:
\[ 88 = 8 \cdot 11 \]
Thus, we can express \(\log_{10} 88\) as:
\[ \log_{10} 88 = \log_{10} 8 + \log_{10} 11 \]
Given that \(\log_{10} 8 = 0.9031\) and \(\log_{10} 11 = 1.0414\), we can now calculate \(\log_{10} 88\):
\[ \log_{10} 88 = 0.9031 + 1.0414 \]
Calculating this:
\[ \log_{10} 88 = 1.9445 \]
Now we can match this result with the options provided:
- \(\log 88 = 0.1383\)
- \(\log 88 = 1.1531\)
- \(\log 88 = 0.9405\)
- \(\log 88 = 1.9445\)
The correct value \( \log 88 = 1.9445 \) corresponds to option 4.
Thus, the answer is:
4) log 88 = 1.9445