Asked by Anonymous
University students, studying the activity of a particular radioactive isotope which had a half-life of 12.0 hours. If the original activity of the sample was 448 kBq, what would the activity be 3.00 days later?
Answers
Answered by
drwls
Three days is six 12-hour intervals, which is six half-lives.
Multiply the original activity by (1/2)^6 = 1/64
448/64 =__ kBq
Multiply the original activity by (1/2)^6 = 1/64
448/64 =__ kBq
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