Let the ages of the three siblings be represented by \( x \), \( x + 1 \), and \( x + 2 \), with \( x + 2 \) being Sophie’s age as she is the oldest.
The sum of their ages can be expressed as:
\[ x + (x + 1) + (x + 2) = 5151 \]
Simplifying the left side gives:
\[ 3x + 3 = 5151 \]
Next, we subtract 3 from both sides:
\[ 3x = 5148 \]
Now, we divide both sides by 3 to find \( x \):
\[ x = \frac{5148}{3} = 1716 \]
Thus, the ages of the siblings are:
- \( x = 1716 \)
- \( x + 1 = 1717 \)
- \( x + 2 = 1718 \)
Sophie, being the oldest sibling, is:
\[ \boxed{1718} \]
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