Question
I need help with two problem please.
4m^+20m+25=
over the m is 2.
w3+5w^-w=5
Please help me. over the w is three and 5w is 2. so could please help me this had to be done tonight.
4m^+20m+25=
over the m is 2.
w3+5w^-w=5
Please help me. over the w is three and 5w is 2. so could please help me this had to be done tonight.
Answers
Reiny
first one, I think you mean
4m^2 + 20m + 25 = 0
this is a perfect square and factors to
(2m+5)(2m+5) = 0
(2m+5)^2 = 0
m = -5/2
second one, I think you mean
w^3 + 5w^2 - w = 5
factor it by grouping
w^2(w+5) - (w+5) = 0
(w+5)(w^2 - 1) = 0
((w+5)(w+1)(w-1) = 0
w = -5, ± 1
4m^2 + 20m + 25 = 0
this is a perfect square and factors to
(2m+5)(2m+5) = 0
(2m+5)^2 = 0
m = -5/2
second one, I think you mean
w^3 + 5w^2 - w = 5
factor it by grouping
w^2(w+5) - (w+5) = 0
(w+5)(w^2 - 1) = 0
((w+5)(w+1)(w-1) = 0
w = -5, ± 1