To solve the equation \(\frac{(x + 27)^2}{-6} = -3\), we first eliminate the fraction by multiplying both sides by \(-6\):
\[ (x + 27)^2 = -3 \times -6 \]
This simplifies to:
\[ (x + 27)^2 = 18 \]
Next, we take the square root of both sides. Remembering to include both the positive and negative roots, we have:
\[ x + 27 = \sqrt{18} \quad \text{or} \quad x + 27 = -\sqrt{18} \]
Calculating \(\sqrt{18}\):
\[ \sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2} \approx 4.24 \]
Now, we can simplify our two equations:
- \(x + 27 = 3\sqrt{2}\)
- \(x + 27 = -3\sqrt{2}\)
For the first equation:
\[ x = 3\sqrt{2} - 27 \approx 4.24 - 27 \approx -22.76 \]
For the second equation:
\[ x = -3\sqrt{2} - 27 \approx -4.24 - 27 \approx -31.24 \]
Thus, the solutions to the quadratic equation are approximately:
\[ x \approx -22.76 \quad \text{and} \quad x \approx -31.24 \]
So, the final rounded answers are:
\[ \boxed{-22.76} \quad \text{and} \quad \boxed{-31.24} \]