Asked by Lee Hooni 🖤
For each value of x, determine whether it is a solution to -5+6x≤37. ? 00 Is it a solution? Yes No 0 10 -3 7
Answers
Answered by
Lee Hooni 🖤
one of them are in corect and its not 0
Answered by
GPT-4o mini
To determine whether each value of \( x \) is a solution to the inequality \( -5 + 6x \leq 37 \), we can solve the inequality for \( x \) first.
1. Start with the inequality:
\[
-5 + 6x \leq 37
\]
2. Add 5 to both sides:
\[
6x \leq 37 + 5
\]
\[
6x \leq 42
\]
3. Divide both sides by 6:
\[
x \leq 7
\]
Now we can check each value of \( x \):
1. **For \( x = 0 \)**:
\[
6(0) = 0 \quad \Rightarrow \quad -5 + 0 = -5 \leq 37
\]
Yes, it is a solution.
2. **For \( x = 10 \)**:
\[
6(10) = 60 \quad \Rightarrow \quad -5 + 60 = 55 \not\leq 37
\]
No, it is not a solution.
3. **For \( x = -3 \)**:
\[
6(-3) = -18 \quad \Rightarrow \quad -5 - 18 = -23 \leq 37
\]
Yes, it is a solution.
4. **For \( x = 7 \)**:
\[
6(7) = 42 \quad \Rightarrow \quad -5 + 42 = 37 \leq 37
\]
Yes, it is a solution.
So, summarizing the results:
- \( x = 0 \): Yes
- \( x = 10 \): No
- \( x = -3 \): Yes
- \( x = 7 \): Yes
1. Start with the inequality:
\[
-5 + 6x \leq 37
\]
2. Add 5 to both sides:
\[
6x \leq 37 + 5
\]
\[
6x \leq 42
\]
3. Divide both sides by 6:
\[
x \leq 7
\]
Now we can check each value of \( x \):
1. **For \( x = 0 \)**:
\[
6(0) = 0 \quad \Rightarrow \quad -5 + 0 = -5 \leq 37
\]
Yes, it is a solution.
2. **For \( x = 10 \)**:
\[
6(10) = 60 \quad \Rightarrow \quad -5 + 60 = 55 \not\leq 37
\]
No, it is not a solution.
3. **For \( x = -3 \)**:
\[
6(-3) = -18 \quad \Rightarrow \quad -5 - 18 = -23 \leq 37
\]
Yes, it is a solution.
4. **For \( x = 7 \)**:
\[
6(7) = 42 \quad \Rightarrow \quad -5 + 42 = 37 \leq 37
\]
Yes, it is a solution.
So, summarizing the results:
- \( x = 0 \): Yes
- \( x = 10 \): No
- \( x = -3 \): Yes
- \( x = 7 \): Yes
Answered by
GPT-4o mini
Let's go through the values one by one again to ensure we evaluate them correctly against the inequality \( -5 + 6x \leq 37 \).
### Given inequality:
\[
-5 + 6x \leq 37
\]
### Solving the inequality:
1. Add 5 to both sides:
\[
6x \leq 42
\]
2. Divide both sides by 6:
\[
x \leq 7
\]
### Now, let's check each value:
1. **For \( x = 0 \)**:
\[
-5 + 6(0) = -5 \quad \Rightarrow \quad -5 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = 0 \) is a solution.
2. **For \( x = 10 \)**:
\[
-5 + 6(10) = -5 + 60 = 55 \quad \Rightarrow \quad 55 \leq 37 \quad \text{(False)}
\]
**Conclusion**: No, \( x = 10 \) is not a solution.
3. **For \( x = -3 \)**:
\[
-5 + 6(-3) = -5 - 18 = -23 \quad \Rightarrow \quad -23 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = -3 \) is a solution.
4. **For \( x = 7 \)**:
\[
-5 + 6(7) = -5 + 42 = 37 \quad \Rightarrow \quad 37 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = 7 \) is a solution.
### Summary of Correct Answers:
- \( x = 0 \): Yes
- \( x = 10 \): No
- \( x = -3 \): Yes
- \( x = 7 \): Yes
Thus, \( x = 0 \) was indeed a solution. If there's a specific error you suspect, please clarify, and we can re-evaluate that particular value!
### Given inequality:
\[
-5 + 6x \leq 37
\]
### Solving the inequality:
1. Add 5 to both sides:
\[
6x \leq 42
\]
2. Divide both sides by 6:
\[
x \leq 7
\]
### Now, let's check each value:
1. **For \( x = 0 \)**:
\[
-5 + 6(0) = -5 \quad \Rightarrow \quad -5 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = 0 \) is a solution.
2. **For \( x = 10 \)**:
\[
-5 + 6(10) = -5 + 60 = 55 \quad \Rightarrow \quad 55 \leq 37 \quad \text{(False)}
\]
**Conclusion**: No, \( x = 10 \) is not a solution.
3. **For \( x = -3 \)**:
\[
-5 + 6(-3) = -5 - 18 = -23 \quad \Rightarrow \quad -23 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = -3 \) is a solution.
4. **For \( x = 7 \)**:
\[
-5 + 6(7) = -5 + 42 = 37 \quad \Rightarrow \quad 37 \leq 37 \quad \text{(True)}
\]
**Conclusion**: Yes, \( x = 7 \) is a solution.
### Summary of Correct Answers:
- \( x = 0 \): Yes
- \( x = 10 \): No
- \( x = -3 \): Yes
- \( x = 7 \): Yes
Thus, \( x = 0 \) was indeed a solution. If there's a specific error you suspect, please clarify, and we can re-evaluate that particular value!
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