To determine which equations have infinitely many solutions, we need to simplify each equation and see if they result in a true statement (like \(0 = 0\)) or a false statement (like \(0 = 5\)). Equations that are the same on both sides will have infinitely many solutions. Let's analyze each option.
A. \(6(x-9) = 6x - 54 + x\)
Distributing on the left side:
\[
6x - 54 = 6x - 54 + x
\]
Simplifying the right side:
\[
6x - 54 = 7x - 54
\]
Subtract \(6x\) from both sides:
\[
-54 = x - 54
\]
Add \(54\) to both sides:
\[
0 = x
\]
This has one solution (\(x = 0\)), not infinitely many.
B. \(5(x - 8) + 10 = 5(x + 2)\)
Distributing on the left side:
\[
5x - 40 + 10 = 5x + 10
\]
This simplifies to:
\[
5x - 30 = 5x + 10
\]
Subtract \(5x\) from both sides:
\[
-30 = 10
\]
This is a false statement, so it has no solutions.
C. \(20 - 8x - 6 = 2(7 - 4x)\)
Simplifying the left side:
\[
14 - 8x = 14 - 8x
\]
Both sides are identical, indicating this equation has infinitely many solutions.
D. \(4(x+4) = 2(2x+5) + 6\)
Distributing:
\[
4x + 16 = 4x + 10 + 6
\]
Simplifying the right side:
\[
4x + 16 = 4x + 16
\]
Again, both sides are identical, indicating this equation also has infinitely many solutions.
E. \(2x + 9 = 18 + 2x\)
Subtracting \(2x\) from both sides gives:
\[
9 = 18
\]
This is a false statement, so it has no solutions.
Summary:
The equations with infinitely many solutions are:
- C. \(20 - 8x - 6 = 2(7 - 4x)\)
- D. \(4(x+4) = 2(2x+5) + 6\)
So the correct answers are C and D.