Asked by Joe
Can someone please condense this expression. I do not know how.
1/2ln(x^2+1)-4ln1/2-1/2[ln(x-4)+lnx]
1/2ln(x^2+1)-4ln1/2-1/2[ln(x-4)+lnx]
Answers
Answered by
Reiny
= (1/2) [ln(x^2+1) - ln((x-4)/x) ] - 4(ln1 - ln2)
= (1/2)ln [ x(x^2+1)/(x-4) ] - 4(0 - ln2)
= ln √ [x(x^2+1)/(x-4)] + ln 16
= ln [16√ [x(x^2+1)/(x-4)]]
= (1/2)ln [ x(x^2+1)/(x-4) ] - 4(0 - ln2)
= ln √ [x(x^2+1)/(x-4)] + ln 16
= ln [16√ [x(x^2+1)/(x-4)]]
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