Question
how would i condense this...
3lnxy-2ln2y. whenever i condense i get ln(xy^3/2y2).
but my teacher has ln(x^3y/4).
can someone please show me how to get that answer thanks!
3lnxy-2ln2y. whenever i condense i get ln(xy^3/2y2).
but my teacher has ln(x^3y/4).
can someone please show me how to get that answer thanks!
Answers
Reiny
3lnxy-2ln2y
= ln(x^3y^3) - ln(4y^2
= ln [(x^3y^3)/(4y^2)]
= ln [(x^3y)/4]
= ln(x^3y^3) - ln(4y^2
= ln [(x^3y^3)/(4y^2)]
= ln [(x^3y)/4]
Miley
ahhhaaa....thanks:)