Question
A rectangular vegetable garden will have a width that is 4
feet less than the length, and an area of 140
square feet. If x represents the length, then the length can be found by solving the equation:
x(x-4)=140
What is the length, x, of the garden?
The length is blank feet.
feet less than the length, and an area of 140
square feet. If x represents the length, then the length can be found by solving the equation:
x(x-4)=140
What is the length, x, of the garden?
The length is blank feet.
Answers
GPT-4o mini
To find the length \( x \) of the garden, we can solve the equation given:
\[
x(x - 4) = 140
\]
First, expand the left side:
\[
x^2 - 4x = 140
\]
Next, move all terms to one side of the equation to set it to zero:
\[
x^2 - 4x - 140 = 0
\]
Now we can use the quadratic formula to solve for \( x \). The quadratic formula is:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In our equation, \( a = 1 \), \( b = -4 \), and \( c = -140 \).
We calculate the discriminant:
\[
b^2 - 4ac = (-4)^2 - 4(1)(-140) = 16 + 560 = 576
\]
Now plug the values into the quadratic formula:
\[
x = \frac{-(-4) \pm \sqrt{576}}{2(1)}
\]
\[
x = \frac{4 \pm 24}{2}
\]
This gives us two possible solutions for \( x \):
1. \( x = \frac{4 + 24}{2} = \frac{28}{2} = 14 \)
2. \( x = \frac{4 - 24}{2} = \frac{-20}{2} = -10 \)
Since a length cannot be negative, we discard \( -10 \) as a solution.
Thus, the length \( x \) of the garden is:
\[
\boxed{14} \text{ feet.}
\]
\[
x(x - 4) = 140
\]
First, expand the left side:
\[
x^2 - 4x = 140
\]
Next, move all terms to one side of the equation to set it to zero:
\[
x^2 - 4x - 140 = 0
\]
Now we can use the quadratic formula to solve for \( x \). The quadratic formula is:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In our equation, \( a = 1 \), \( b = -4 \), and \( c = -140 \).
We calculate the discriminant:
\[
b^2 - 4ac = (-4)^2 - 4(1)(-140) = 16 + 560 = 576
\]
Now plug the values into the quadratic formula:
\[
x = \frac{-(-4) \pm \sqrt{576}}{2(1)}
\]
\[
x = \frac{4 \pm 24}{2}
\]
This gives us two possible solutions for \( x \):
1. \( x = \frac{4 + 24}{2} = \frac{28}{2} = 14 \)
2. \( x = \frac{4 - 24}{2} = \frac{-20}{2} = -10 \)
Since a length cannot be negative, we discard \( -10 \) as a solution.
Thus, the length \( x \) of the garden is:
\[
\boxed{14} \text{ feet.}
\]