Asked by Semaj
a vegetable garden is in the shape of a rectangle, surrounded by 296 feet of fence. the length of the garden is 61 feet more than twice the width of the garden. fins the dimensions of this garden
Answers
Answered by
Jimmy Neutron
l (length) = x + 61
w (width) = x
P (perimeter) = 296 ft = 2l ft + 2w ft = 2(x+61) ft + 2x ft = 4x ft + 122 ft
4x = 296 ft - 122 ft = 174 ft
x = 174 ft/4 = 87 ft/2 = 43.5 ft
thus,
l = 43.5 ft + 61 ft = 104.5 ft
and
w = 43.5 ft
ur welcome :)
w (width) = x
P (perimeter) = 296 ft = 2l ft + 2w ft = 2(x+61) ft + 2x ft = 4x ft + 122 ft
4x = 296 ft - 122 ft = 174 ft
x = 174 ft/4 = 87 ft/2 = 43.5 ft
thus,
l = 43.5 ft + 61 ft = 104.5 ft
and
w = 43.5 ft
ur welcome :)
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