Question

Ammonia and gaseious hydrogen chloride combine to form ammonium chloride.

NH3(g) + HCl(g) = NH4Cl(s) (balanced)

If 4.21 L of NH3(g) at 27 C and 1.02 atm is combined with 5.35 L of HCl at 26 C and 0.998 atm, what mass of NH4Cl will be produced? Which gas is the limiting reactant? Which gas is present in excess?

PLEASE HELP!

Answer 1

Use PV = nRT (once for each gas) to determine moles. Since the reaction is a 1:1 reaction (1 mole NH3 to 1 mole HCl), the reactant with the smaller number of moles will be the limiting reagent and convert that number of moles to grams NH4Cl.

Answer 2

So HCL would be the limiting reactant, right? And NH3 is present in excess. So do I convert 0.218 mol HCl to grams of NH4Cl?

Thanks btw for helping me. :)

Answer 3

no

Answer 4

wery no.