Question

An archer applies an average force of 200 N to draw the bow string back 1.3 m.

a)How much work did the archer do on the string?

b)How much mechanical potential energy is stored in the stretched bow?
c)How much kinetic energy does the arrow have before it is released?

d)How much potential energy will the arrow have after it leaves the bowstring?

e)If a 0.3 kg arrow is shot from this bow, then how fast will it be moving just after it leaves the bowstring?

Answers

bobpursley
I will be happy to critique your work.
Adrionna
OK SO PLEASE EXPLAIN TO ME HOW TO DO THIS
bobpursley
a. work=avgforce*distance
b.PE=above work. KEwhenreleased=InitialPE
d. zero, no PE, it has KE.
e. Initial energy=1/2 m v^2
solve for v.
Anonymous
Idk wat it is
JIGGLY BINGUS
SOMEONE TELL ME HOW TO DO THESE RN PLSPPLSPLSPLSPL

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