An archer exerts an average force of 194 N to draw a 0.25 kg arrow back 1.2 m with the string of the bow.

How much work does the archer exert?

User Icon for drwls drwls answered
11 years ago

The "bow constant", which is the ratio of force F to pullback distance X, is

k = 194/1.2 = 161.7 N/m

The work done puling back the arrow is
W = (1/2) k X^2 = (1/2) F*X

The mass of the arrow is not needed to answer that question, but it will affect the arrow's velocity