Find the value of xif A=26, B=4x+45A=26, B=4x+45 and C=47 of a 180 triangel

x=x=x=

1 answer

To find the value of \( x \) in the context of triangle \( ABC \), we know the following:

  • The sum of the angles in a triangle is \( 180^\circ \).
  • \( A = 26^\circ \)
  • \( B = 4x + 45^\circ \)
  • \( C = 47^\circ \)

We can use the formula for the sum of the angles in a triangle:

\[ A + B + C = 180 \]

Substituting the given values into the equation:

\[ 26 + (4x + 45) + 47 = 180 \]

Now, simplify the left side:

\[ 26 + 45 + 47 = 118 \]

So, we have:

\[ 118 + 4x = 180 \]

Next, isolate \( 4x \):

\[ 4x = 180 - 118 \] \[ 4x = 62 \]

Now, divide both sides by 4:

\[ x = \frac{62}{4} = 15.5 \]

Thus, the value of \( x \) is:

\[ \boxed{15.5} \]