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Ido not understand why the rt triangel was in ratio of 1:√3:2 in Sue's question

where in triangle abc c isthert angle and sin a √3/2 - find csc b-please explain where the 1 comes from

2 answers

(We know that in rt triangle
Sin=P/H)

given sinA=_/3/2

SO P=_/3 , H=2

ACB is rt triangle
by pythagoras theorem

H^2=P^2+B^2

B^2=H^2-P^2

B^2=(2)^2-(_/3)^2

B^2=4-3

B^2=1

B=_/1

B=1

(where P=perpendicular,
B=base,H=hypotenuse)
thank you.