Asked by CHeM
Copper has a unit cell volume of (47.453 A^3) and a face centered unit cell. How would I go about finding the volume of atoms within the unit cell? Would you use Avogadro's # somehow?
Answers
Answered by
DrBob222
I don't get the 47.453 A^3 for volume. That seems far too large (of course that depends upon what A stands for).
Whatever the volume, then
V<sup>1/3</sup> = length of an edge of the unit cell = a. Then 4r = a(2<sup>1/2</sub>).
When you have found r (radius of the atom), then volume of the atom = (4/3)*pi*r<sup>3</sup>.
Whatever the volume, then
V<sup>1/3</sup> = length of an edge of the unit cell = a. Then 4r = a(2<sup>1/2</sub>).
When you have found r (radius of the atom), then volume of the atom = (4/3)*pi*r<sup>3</sup>.
Answered by
DrBob222
4r = a(2<sup>1/2</sup>) and
volume of the atom = (4/3)*pi*r<sup>3</sup>
volume of the atom = (4/3)*pi*r<sup>3</sup>
Answered by
CHeM
I got it thank you!
The A^3 was suppose to stand for ångström
cubed...
The A^3 was suppose to stand for ångström
cubed...
Answered by
j
what does the pi stand for?
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