Asked by Anonymous
A cell is set up with copper and lead electrodes in contact with CuSO4(aq) and Pb(NO3)2(aq), respectively, at 25˚C. The standard reduction potentials are:
Pb2+ + 2e- --> Pb E˚=-0.13 V
Cu2+ + 2e- --> Cu E˚=+.34 V
If sulfuric acid is added to the Pb(NO3)2 solution, forming a precipitate of PbSO4, the cell potential:
Pb2+ + 2e- --> Pb E˚=-0.13 V
Cu2+ + 2e- --> Cu E˚=+.34 V
If sulfuric acid is added to the Pb(NO3)2 solution, forming a precipitate of PbSO4, the cell potential: