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For the square pyramid the lateral edge length e is 25 in and the slant height 8, is 24 in find the height of the pyramid H rou...Asked by WOooo
For the square pyramid, the lateral edge length, e , is 25 in., and the slant height, s , is 24 in. Find the height of the pyramid, h . Round the answer to the nearest whole number. Hint: Before finding the length of h , you will first need to find the length of r . (1 point) The height of the square pyramid is ____ in.
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GPT-4o mini
To find the height \( h \) of the square pyramid, we first need to find the length of \( r \) (the distance from the center of the base of the pyramid to the midpoint of one of its edges).
1. The lateral edge \( e \) of the pyramid is given as 25 in, and the slant height \( s \) is given as 24 in.
2. In a square pyramid, the lateral edge \( e \), the height \( h \), and the slant height \( s \) will form a right triangle with the base radius \( r \).
We can use the Pythagorean theorem in the triangle formed by \( h \), \( r \), and \( s \):
\[
s^2 = r^2 + h^2
\]
Since we need to find \( r \), we can use the relationship between the lateral edge \( e \), slant height \( s \), and radius \( r \):
\[
e^2 = r^2 + h^2 \quad \text{(1)}
\]
\[
s^2 = r^2 + h^2 \quad \text{(2)}
\]
From (1), we substitute \( e = 25 \) and from (2) \( s = 24 \):
\[
25^2 = r^2 + h^2 \quad \text{(1)}
\]
\[
24^2 = r^2 + h^2 \quad \text{(2)}
\]
Calculating the squares:
\[
625 = r^2 + h^2 \quad \text{(1)}
\]
\[
576 = r^2 + h^2 \quad \text{(2)}
\]
Next, we can express the height \( h \) in terms of \( r \) using the slant height equation (2):
1. From equation (2):
\[
r^2 + h^2 = 576
\]
We can express \( h^2 \) as:
\[
h^2 = 576 - r^2
\]
2. Substitute this into equation (1):
\[
625 = r^2 + (576 - r^2)
\]
This simplifies to:
\[
625 = 576
\]
Clearly, solving these equations directly will not yield \( r \), so we use \( s \) to determine \( r \) through the Pythagorean relation:
\[
s^2 = r^2 + h^2
\]
We have already:
\[
576 = r^2 + h^2
\]
Let’s also express the relationship of \( e \) as:
\[
25^2 = r^2 + h^2
\]
or:
\[
625 = r^2 + h^2
\]
From the equations, we have a contradiction because substituting every \( h \) results in the fact that we need to manipulate either directly solving or using \( r \).
Finding \( r \) specifically will yield \( h \).
Using geometry, the \( r \) can be seen as \( 12 \) using the context.
So:
Use:
1. Solve for r in terms of e to give that pyramid height needs reevaluation for \( i \):
\[
r = \sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7
\]
Now substituting back to find height:
\[
h = \sqrt{576 - r^2} = \sqrt{576 - 49} = \sqrt{527}
\]
Calculating gives:
\[
h \approx 23
\]
Rounding-off gives \( h \):
Thus:
The height of the square pyramid is \( 23 \) inches.
1. The lateral edge \( e \) of the pyramid is given as 25 in, and the slant height \( s \) is given as 24 in.
2. In a square pyramid, the lateral edge \( e \), the height \( h \), and the slant height \( s \) will form a right triangle with the base radius \( r \).
We can use the Pythagorean theorem in the triangle formed by \( h \), \( r \), and \( s \):
\[
s^2 = r^2 + h^2
\]
Since we need to find \( r \), we can use the relationship between the lateral edge \( e \), slant height \( s \), and radius \( r \):
\[
e^2 = r^2 + h^2 \quad \text{(1)}
\]
\[
s^2 = r^2 + h^2 \quad \text{(2)}
\]
From (1), we substitute \( e = 25 \) and from (2) \( s = 24 \):
\[
25^2 = r^2 + h^2 \quad \text{(1)}
\]
\[
24^2 = r^2 + h^2 \quad \text{(2)}
\]
Calculating the squares:
\[
625 = r^2 + h^2 \quad \text{(1)}
\]
\[
576 = r^2 + h^2 \quad \text{(2)}
\]
Next, we can express the height \( h \) in terms of \( r \) using the slant height equation (2):
1. From equation (2):
\[
r^2 + h^2 = 576
\]
We can express \( h^2 \) as:
\[
h^2 = 576 - r^2
\]
2. Substitute this into equation (1):
\[
625 = r^2 + (576 - r^2)
\]
This simplifies to:
\[
625 = 576
\]
Clearly, solving these equations directly will not yield \( r \), so we use \( s \) to determine \( r \) through the Pythagorean relation:
\[
s^2 = r^2 + h^2
\]
We have already:
\[
576 = r^2 + h^2
\]
Let’s also express the relationship of \( e \) as:
\[
25^2 = r^2 + h^2
\]
or:
\[
625 = r^2 + h^2
\]
From the equations, we have a contradiction because substituting every \( h \) results in the fact that we need to manipulate either directly solving or using \( r \).
Finding \( r \) specifically will yield \( h \).
Using geometry, the \( r \) can be seen as \( 12 \) using the context.
So:
Use:
1. Solve for r in terms of e to give that pyramid height needs reevaluation for \( i \):
\[
r = \sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7
\]
Now substituting back to find height:
\[
h = \sqrt{576 - r^2} = \sqrt{576 - 49} = \sqrt{527}
\]
Calculating gives:
\[
h \approx 23
\]
Rounding-off gives \( h \):
Thus:
The height of the square pyramid is \( 23 \) inches.
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