To find the height \( h \) of the square pyramid, we first need to find the length of \( r \) (the distance from the center of the base of the pyramid to the midpoint of one of its edges).
- The lateral edge \( e \) of the pyramid is given as 25 in, and the slant height \( s \) is given as 24 in.
- In a square pyramid, the lateral edge \( e \), the height \( h \), and the slant height \( s \) will form a right triangle with the base radius \( r \).
We can use the Pythagorean theorem in the triangle formed by \( h \), \( r \), and \( s \):
\[ s^2 = r^2 + h^2 \]
Since we need to find \( r \), we can use the relationship between the lateral edge \( e \), slant height \( s \), and radius \( r \):
\[ e^2 = r^2 + h^2 \quad \text{(1)} \] \[ s^2 = r^2 + h^2 \quad \text{(2)} \]
From (1), we substitute \( e = 25 \) and from (2) \( s = 24 \):
\[ 25^2 = r^2 + h^2 \quad \text{(1)} \] \[ 24^2 = r^2 + h^2 \quad \text{(2)} \]
Calculating the squares:
\[ 625 = r^2 + h^2 \quad \text{(1)} \] \[ 576 = r^2 + h^2 \quad \text{(2)} \]
Next, we can express the height \( h \) in terms of \( r \) using the slant height equation (2):
- From equation (2):
\[ r^2 + h^2 = 576 \]
We can express \( h^2 \) as:
\[ h^2 = 576 - r^2 \]
- Substitute this into equation (1):
\[ 625 = r^2 + (576 - r^2) \]
This simplifies to:
\[ 625 = 576 \]
Clearly, solving these equations directly will not yield \( r \), so we use \( s \) to determine \( r \) through the Pythagorean relation:
\[ s^2 = r^2 + h^2 \]
We have already:
\[ 576 = r^2 + h^2 \]
Let’s also express the relationship of \( e \) as:
\[ 25^2 = r^2 + h^2 \] or: \[ 625 = r^2 + h^2 \]
From the equations, we have a contradiction because substituting every \( h \) results in the fact that we need to manipulate either directly solving or using \( r \).
Finding \( r \) specifically will yield \( h \).
Using geometry, the \( r \) can be seen as \( 12 \) using the context.
So:
Use:
- Solve for r in terms of e to give that pyramid height needs reevaluation for \( i \):
\[ r = \sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7 \]
Now substituting back to find height:
\[ h = \sqrt{576 - r^2} = \sqrt{576 - 49} = \sqrt{527} \]
Calculating gives:
\[ h \approx 23 \]
Rounding-off gives \( h \):
Thus: The height of the square pyramid is \( 23 \) inches.